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http://www.aceorganicchem.com This video gives seven clues to help students decipher organic chemistry problems.
lol me too... wtf
By cmonutube [Affiliate User] 1224124962 Reply Spam [+0] Moderate Up Moderate Down RemoveAwesome
By julieha80 [Affiliate User] 1220642853 Reply Spam [+0] Moderate Up Moderate Down Removeat what level ochem is this based?
By PsychoTropica [Affiliate User] 1216896760 Reply Spam [+0] Moderate Up Moderate Down RemoveO S**t this class is going to ruin my GPA dam
By tomdamho [Affiliate User] 1215913063 Reply Spam [+0] Moderate Up Moderate Down RemoveYou can completely reduce the ketone to a CH2with a Wolf-Kishner reaction, using NH2NH2 in a a strong base like KOH. I like to think of it as a bald guy (ketone O)who grows the Hair of the Wolff (to H's bonded to the Carbon instead). Silly, but it's stuck with me so far.
By englishgalmd [Affiliate User] 1211990292 Reply Spam [+0] Moderate Up Moderate Down RemoveAwesome !! but this is like a small fraction of Ochem
By shermyeung11 [Affiliate User] 1209624251 Reply Spam [+0] Moderate Up Moderate Down Removeawesome!!!!
By unsteadyequilibrium [Affiliate User] 1208619109 Reply Spam [+0] Moderate Up Moderate Down Removei loved the little quotes at the bottom CUTE
By sugarstorm05 [Affiliate User] 1207806553 Reply Spam [+0] Moderate Up Moderate Down RemoveMy professor said it is possible but with a different set of conditions.
By nadia444 [Affiliate User] 1206817370 Reply Spam [+0] Moderate Up Moderate Down RemoveThis is true, however, the equilibrium SO highly favors the equatorial that is essential "locked". Undergraduates don't need to be confused and think that they can do chemistry that is impossible b/c there is 0.001% axial. It might be clearer to put "locked" in quotes i guess.
By ochem9 [Affiliate User] 1206184674 Reply Spam [+0] Moderate Up Moderate Down Removet-butylcyclohexane is not locked, there is a rapid equilibrium between axial and equatorial forms, where the equatorial form is highly favored.
By mfmayer [Affiliate User] 1206165962 Reply Spam [+0] Moderate Up Moderate Down RemoveNice video!
By jerrykim2 [Affiliate User] 1206090081 Reply Spam [+0] Moderate Up Moderate Down Removecan we reduce the ketone under H2/Pd?
I think yes, but oxitations and reductions are my weak point
Oh Admiral Ackbar, you and your crazy traps ... :)
By DesShai [Affiliate User] 1203936207 Reply Spam [+0] Moderate Up Moderate Down Removegreat video. Actually, you can reduce the ketone in clue 4 to a secondary alcohol under those conditions.
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